Cavaliers sign Jordan Bell, Dean Wade to multi-year deals

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By , 92.3 The Fan
Cleveland, OH (92.3 The Fan) - The Cleveland Cavaliers have agreed to multi-year deals with forward Dean Wade and the incoming Jordan Bell. Cavs General Manager Koby Altman made the official announcement on Tuesday
ESPN's Adrian Wojnarowski first reported Wade's signing on Monday.
Wade, who appeared in 12 games for the Cavs last season, sees his original two-way deal converted into a contract reportedly for four years, according to Cleveland.com's Chris Fedor. Wade spent most of this past season with the team's Canton affiliate, but he shot 39.9% from the 3-point line in the G-League, along with averages of 14.2 points and 7.5 rebounds.

With this deal, Wade is set to make $375,000 for the remainder of the season, with the next three years non-guaranteed. He will remain with the Cavaliers after reports said Wade was garnering interest from the Washington Wizards.

Meanwhile, the Cavs add another big man in the multi-year deal with Bell, a six-foot-eight power forward/center who was cut by the Memphis Grizzlies back in March. Bell split this past season between Memphis and the Minnesota Timberwolves, where he averaged 3.2 points and 2.8 rebounds per game, as well as 33.3% shooting from beyond the arc.

Bell was drafted by Golden State (via a trade with Chicago) in the second round of the 2017 NBA Draft, and was part of the Warriors' 2018 NBA Finals victory over the Cavaliers.

Fedor and Cleveland.com first reported Bell's signing with the Cavs.

Both signings of Bell and Wade fill the remaining two spots in the Cavaliers' roster.